Tools, FAQ, Tutorials:
Extending json.JSONEncoder Class
How to extend json.JSONEncoder class? I want to encode other Python data types to JSON.
✍: FYIcenter.com
If you encode your own data types to JSON strings,
you need to extend the json.JSONEncoder class and override the default()
function.
The following Python example shows you how to extend json.JSONEncoder class to encode "complex" data type into JSON format:
C:\fyicenter>type MyJSONEncoder.py
# MyJSONEncoder.py
# Copyright (c) FYIcenter.com
import json
class MyJSONEncoder(json.JSONEncoder):
def default(self, obj):
if isinstance(obj, complex):
return {'r': obj.real, 'i': obj.imag}
return json.JSONEncoder.default(self, obj)
encoder = MyJSONEncoder(indent=4)
i = 2
f = 2.1
c = 2 + 1j
o = {'int': i, 'float': f, 'complex': c}
j = encoder.encode(o)
print(j)
C:\fyicenter>python MyJSONEncoder.py
{
"int": 2,
"float": 2.1,
"complex": {
"r": 2.0,
"i": 1.0
}
}
⇒ json.loads() - Loading JSON into Object
⇐ What Is json.JSONEncoder Class
2018-10-08, ∼5574🔥, 0💬
Popular Posts:
How to install .NET Framework in Visual Studio Community 2017? I have the Visual Studio Installer in...
Why I am getting "The Windows SDK version 8.1 was not found" error, when building my C++ application...
Tools, FAQ, Tutorials: JSON Validator JSON-XML Converter XML-JSON Converter JSON FAQ/Tutorials Pytho...
How To Protect Special Characters in Query String in PHP? If you want to include special characters ...
How to use the "send-one-way-request" Policy statement to call an extra web service for an Azure API...