Passing an Argument to a Function in PHP

Home > PHP

Q

How To Pass an Argument to a Function? in PHP?

✍: FYIcenter.com

A

To pass an argument to a function, you need to:

Add an argument definition in the function definition.
Add a value as an argument when invoking the function.

Here is a PHP script on how to use arguments in a function():

<?php 
function f2c($f) {
  return ($f - 32.0)/1.8;
}
print("Celsius: ".f2c(100.0)."\n");
print("Celsius: ".f2c(-40.0)."\n");
?>

This script will print:

Celsius: 37.777777777778
Celsius: -40

⇒ Variables Are Passed by Values in PHP

⇐ Returning a Value from a Function in PHP

⇑ Creating Your Own Functions in PHP

⇑⇑ PHP Tutorials

2016-12-24, 1295👍, 0💬

Creating Your Own Functions in PHP
Where to find tutorials on how to create Your Own Functions in PHP? A collection of tutorials to answer many frequently asked questions on Creating Your Own Functions in PHP. Topics included in this collection are: Defining a User Function in PHP Invoking a User Function in PHP Returning a Value fro... 2016-12-28, 2276👍, 0💬

Passing Arrays to Function in PHP
Can You Pass an Array into a Function? in PHP? You can pass an array into a function in the same as a normal variable. No special syntax needed. Here is a PHP script on how to pass an array to a function: <?php function average($array) { $sum = array_sum($array); $count = count($array); retur... 2016-12-18, 1432👍, 0💬

Defining a User Function in PHP
How To Define a User Function? in PHP? You can define a user function anywhere in a PHP script using the function statement like this: "function name() {...}". Here is a PHP script example on how to define a user function: <?php function msg() { print("Hello world!\n"); } msg(); ?> Thi... 2016-12-28, 1375👍, 0💬

Passing Arrays by Values to Functions in PHP
How Arrays Are Passed Through Arguments? in PHP? Like a normal variable, an array is passed through an argument by value, not by reference. That means when an array is passed as an argument, a copy of the array will be passed into the function. Modifying that copy inside the function will not impact... 2016-12-18, 1332👍, 0💬

Defining an Argument as a Reference in PHP
Can You Define an Argument as a Reference Type? in PHP? You can define an argument as a reference type in the function definition. This will automatically convert the calling arguments into references. Here is a PHP script on how to define an argument as a reference type: <?php function ref_s... 2016-12-24, 1323👍, 0💬

Invoking a User Function in PHP
How To Invoke a User Function? in PHP? You can invoke a function by entering the function name followed by a pair of parentheses. If needed, function arguments can be specified as a list of expressions enclosed in parentheses. Here is a PHP script example on how to invoke a user function: <?p... 2016-12-28, 1302👍, 0💬

Passing an Argument to a Function in PHP
How To Pass an Argument to a Function? in PHP? To pass an argument to a function, you need to: Add an argument definition in the function definition. Add a value as an argument when invoking the function. Here is a PHP script on how to use arguments in a function(): <?php function f2c($f) { r... 2016-12-24, 1296👍, 0💬

Passing Variables by References in PHP
How To Pass Variables By References? in PHP? You can pass a variable by reference to a function by taking the reference of the original variable, and passing that reference as the calling argument. Here is a PHP script on how to use pass variables by references: <?php function swap($a, $b) { ... 2016-12-24, 1283👍, 0💬

Variables Are Passed by Values in PHP
How Variables Are Passed Through Arguments? in PHP? Like more of other programming languages, variables are passed through arguments by values, not by references. That means when a variable is passed as an argument, a copy of the value will be passed into the function. Modifying that copy inside the... 2016-12-24, 1277👍, 0💬

All rights in the contents of this web site are reserved by the individual author. fyicenter.com does not guarantee the truthfulness, accuracy, or reliability of any contents.