Invoking a User Function in PHP

Q

How To Invoke a User Function? in PHP?

✍: FYIcenter.com

A

You can invoke a function by entering the function name followed by a pair of parentheses. If needed, function arguments can be specified as a list of expressions enclosed in parentheses. Here is a PHP script example on how to invoke a user function:

<?php 
function hello($f) {
  print("Hello $f!\n");
}
hello("Bob");
?>

This script will print:

Hello Bob!

⇒ Returning a Value from a Function in PHP

⇐ Defining a User Function in PHP

⇑ Creating Your Own Functions in PHP

⇑⇑ PHP Tutorials

2016-12-28, ∼2012🔥, 0💬

Creating Your Own Functions in PHP
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Defining a User Function in PHP
How To Define a User Function? in PHP? You can define a user function anywhere in a PHP script using the function statement like this: "function name() {...}". Here is a PHP script example on how to define a user function: <?php function msg() { print("Hello world!\n"); } msg(); ?> Thi... 2016-12-28, ∼2183🔥, 0💬

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Defining an Argument as a Reference in PHP
Can You Define an Argument as a Reference Type? in PHP? You can define an argument as a reference type in the function definition. This will automatically convert the calling arguments into references. Here is a PHP script on how to define an argument as a reference type: <?php function ref_s... 2016-12-24, ∼2081🔥, 0💬

Variables Are Passed by Values in PHP
How Variables Are Passed Through Arguments? in PHP? Like more of other programming languages, variables are passed through arguments by values, not by references. That means when a variable is passed as an argument, a copy of the value will be passed into the function. Modifying that copy inside the... 2016-12-24, ∼2033🔥, 0💬

Invoking a User Function in PHP
How To Invoke a User Function? in PHP? You can invoke a function by entering the function name followed by a pair of parentheses. If needed, function arguments can be specified as a list of expressions enclosed in parentheses. Here is a PHP script example on how to invoke a user function: <?p... 2016-12-28, ∼2013🔥, 0💬

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