Tools, FAQ, Tutorials:
json_last_error_msg() - PHP JSON Error Message
How to detect errors occurred in the json_decode() call?
✍: FYIcenter.com
You can use the following two functions to detect error and display error message
occurred during the last call of json_decode() or json_encode().
Here is a PHP example that shows you how to detect and display errors of a json_decode() call:
<?php
# json_decode_error.php
# Copyright (c) FYIcenter.com
$json = '{"site":"dev.fyicenter.com","topics":{"PHP":"Y","JSON":"Y"]}';
print("\nInput: ".$json."\n");
# Decoded into an array
$array = json_decode($json,true);
if (json_last_error() == JSON_ERROR_NONE) {
print("\nOutput Array:\n");
print(" Type: ".gettype($array)."\n");
print(" Size: ".count($array)."\n");
print(" ['site']: ".$array["site"]."\n");
print(" ['topics']['JSON']: ".$array["topics"]["JSON"]."\n");
print("\nOutput Array Dump:\n");
var_dump($array);
} else {
print("\njson_decode() error: ".json_last_error_msg()."\n");
}
?>
If you run the above PHP code through the PHP engine, you get the following output:
>\fyicenter\php\php.exe json_decode_error.php
Input: {"site":"dev.fyicenter.com","topics":{"PHP":"Y","JSON":"Y"]}
json_decode() error: State mismatch (invalid or malformed JSON)
Unfortunately, the error message is not detailed enough to tell us where the error occurred in the JSON text string.
⇒ json_encode() Function in PHP
2018-03-04, ∼5282🔥, 0💬
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