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Why doesnt sizeof properly report the size of an array
C Interview Questions and Answers
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Why doesnt sizeof properly report the size of an array
Q: Why doesn't sizeof properly report the size of an array when the array is a parameter to a function? I have a test routine
f(char a[10])
{
int i = sizeof(a);
printf("%d\n", i);
}
and it prints 4, not 10.
A: The compiler pretends that the array parameter was declared as a pointer (that is, in the example, as char *a; , and sizeof reports the size of the pointer.
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